2[3-2(z+4)]=(4-z)

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Solution for 2[3-2(z+4)]=(4-z) equation:


Simplifying
2[3 + -2(z + 4)] = (4 + -1z)

Reorder the terms:
2[3 + -2(4 + z)] = (4 + -1z)
2[3 + (4 * -2 + z * -2)] = (4 + -1z)
2[3 + (-8 + -2z)] = (4 + -1z)

Combine like terms: 3 + -8 = -5
2[-5 + -2z] = (4 + -1z)
[-5 * 2 + -2z * 2] = (4 + -1z)
[-10 + -4z] = (4 + -1z)

Remove parenthesis around (4 + -1z)
-10 + -4z = 4 + -1z

Solving
-10 + -4z = 4 + -1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add 'z' to each side of the equation.
-10 + -4z + z = 4 + -1z + z

Combine like terms: -4z + z = -3z
-10 + -3z = 4 + -1z + z

Combine like terms: -1z + z = 0
-10 + -3z = 4 + 0
-10 + -3z = 4

Add '10' to each side of the equation.
-10 + 10 + -3z = 4 + 10

Combine like terms: -10 + 10 = 0
0 + -3z = 4 + 10
-3z = 4 + 10

Combine like terms: 4 + 10 = 14
-3z = 14

Divide each side by '-3'.
z = -4.666666667

Simplifying
z = -4.666666667

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